Question

If log2(5x + 7) = 5, then find ‘x’.​

Answer 1

Answer:

5

Step-by-step explanation:

Log2 (5x + 7) = 5

According to Log Formula

Loga N = x then It will become N = a^x

Log2 (5x + 7) = 5

5x + 7 = 2^5

5x + 7 = 32

5x = 32 - 7

5x = 25

x = 25/5

x = 5

Answer 2

Answer:

Required value of x is 5.

Step-by-step explanation:

Given,

$log_{2}(5x + 7) = 5 \\ 5x + 7 = {2}^{5} \\ 5x + 7 = 32 \\ 5x = 32 - 7 \\ 5x = 25 \\ x = \frac{25}{5} \\ x = 5$

Required value of x is 5.

Here applied formula,

$log_{a}(b) = c \\ b = {a}^{c}$

Important Logarithm formulas,

$log_{x}(1) = 0 \\ log_{x}(0) = 1 \\ log_{x}(y) = \frac{ log(x) }{ log(y) } \\ log( {x}^{y} ) = y log(x) \\ log(x) + log(y) = log(xy) \\ log(x) - log(y) = log( \frac{x}{y} ) \\ log_{x}(x) = 1$

Logarithm is a part of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

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