Question

if log2 base 7=m then log28 base


49 equal to​

Answer 1

Answer:

2m/m+2

Step-by-step explanation:

Note:All logs are to the base e

log 7/log 2=m ---eqn(i)

now,

log 49/log 28

=2log7/log(7x4)

2log7/(log7+2log2)

dividing numerator and denominator by log2

2m/(m+2)  -----(using eqn(i))

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