If log2 to the base 10=x log3 to the base 10 = y,then log 12 with base 5 is
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Answer:
log12 with base 5= log12/log5
=(2x+y)/(1-x)
Step-by-step explanation:
log12=log(2*2*3) to the base 10
=log2+log2+log3
=2log2+log3
=2x+y
log5=log(10/2)
=log10-log2
=1-x
log12 with base 5= log12/log5
=(2x+y)/(1-x)
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