If log2 = x, log 3 = y and log 7=z, then the value of log(4.³√63) is
pls solution immediately
Answers
Answered by
4
Step-by-step explanation:
log2 = x, log 3 = y and log 7=z,
log(4.³√63) =log4+log³√63
=log 2^2 +log(63)^1/3
=2log2+1/3log63
=2x+1/3log(7×9)
=2x+1/3log7+1/3log9
=2x+1/3 z+1/3log3^2
=2x+1/3 z+2/3log3
=2x+1/3 z+2/3 y
=2x+2/3 y +1/3 z
Answered by
0
Answer:
Given:
log2y=x
2x=y
log3z=x
3x=z
So,
72x=(2×2×2×3×3)x
=(23×32)x
=(2x)3×(3x)2
=y3×z2
=y3z2
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