Question

If log2 x+log2 y >= 6 then the least value of x +y is
(A) 4
(B) 8
(C) 16
(D) 32​

Answer 1

Answer:

ANSWER

log 2 x+log 2 y≥6

⇒xy≥64 ...(1)

If x>0 & y>0

Since A.M.≥G.M

x+y/2 >√xy

x+y/2 > √64. {from. I}

x+y >16