Question

if log2 (y+1)=2log 2 x+c and y=3 when x=2 find y in terms of x

Answer 1

Answer:

y = x² /2 - 1

Step-by-step explanation:

log2 (y+1)=2log 2 x+c

log2 (4)=2log 4+c

c = -log2

log2 (y+1)=2log 2 x-log2

log2 (y+1)=2log 2 x/2

log2 (y+1)=2log  x

log2 (y+1)=log  x²

2 (y+1) =  x²

(y+1) =  x² /2

y =  x² /2 - 1