Question

If log27base12 = a then the value of log 16 base6

Answer 1

if log 27=a,then log 16 base6 is

(I)4(3-a)/(3+a)

(ii)4(3+a)/(3-a)

(iii)(3+a)/4(3-a)

(iv)(3-a)/4(3+a)