Question

If log2a, log2b are the roots of the equation x^2 + 3x + 2 = 0 then minimum possible value of a + 2b =

Answer 1

Answer:

a=1/20

b=1/200

Step-by-step explanation:

solving given equation,

we get x= -1  and x= -2

which means

log2a= -1=log(10^(-1))

=>2a=10^(-1)

=>2a=1/10

=>a=1/20

log 2b= -2 =log(10^(-2))

=>2b=10^(-2)

=>2b=1/100

=>b=1/200

HOPE IT HELPS,

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Answer 2

Step-by-step explanation:

a=1/20

b=1/200

by solving the equation we get

X=-1,nd x=-2

which means log2a=-1=log(10^(-1))

=>2a=10^(-1)

=>2a=1/10

=>a=1/20

log 2b=-2=log(10^(-2))

=>2b=10^(-2)

2b=1/100

=>b=1/200

hope it helps...