if log2x+log4x+log16x=21/4 then x=?
Answers
Answered by
41
use concept ,
logx + log y = logxy
given,
log2x + log4x +log16x = 21/4
log{ 2x.4x.16x } = 21/4
log { 128x³} = 21/4
log(128) +logx³ = 21/4
7log2 + 3logx = 21/4
3logx = 7{ 3/4 -log2}
logx = 7/3{ 3/4 -log2 }
x = 10^[7/3{3/4-log2}]
logx + log y = logxy
given,
log2x + log4x +log16x = 21/4
log{ 2x.4x.16x } = 21/4
log { 128x³} = 21/4
log(128) +logx³ = 21/4
7log2 + 3logx = 21/4
3logx = 7{ 3/4 -log2}
logx = 7/3{ 3/4 -log2 }
x = 10^[7/3{3/4-log2}]
Answered by
27
Answer:
x = 8
Step-by-step explanation:
...................
Attachments:
Similar questions