Question

If log2x + log4x + log16x = 21/4, these x is equal to

Answer 1

Step-by-step explanation:

$\sqrt[3]{ {10}^{21 \div 4 } \div {2}^{7} }$

Answer 2

Answer:

8

Step-by-step explanation:

use change of base rule then raise all numbers to the power of 2 then take 2 common and transfer remaining number to rhs then use law of exponential u will get 2 to the power of 3 that is 8