if log³ x =log⁹ 16 then x+1=
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0
Answer
Correct option is
B
4
D
log
2
16
log
3
{5+4log
3
(x−1)}=2
⇒5+4log
3
(x−1)=3
2
⇒log
3
(x−1)=1
⇒x−1=3
⇒x=4
Which can be written as x=4=4log
2
2[∵log
a
a=1]=log
2
2
4
=log
2
16
Ans: B, D
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