Question

if log32x + log32(1/8) = 1/5, then the value of x is equal to

Answer 1

log₃₂x  + log₃₂(2⁻³) = 1/5

log₃₂x - 3log₃₂2 = 1/5

log₃₂x = 1/5 + 1/5

32^1/10 = x

x = $\sqrt{2}$

Answer 2

Answer:

x=16

Step-by-step explanation:

Using, $log_{a}x+log_{a}y=log_{a}xy$

⇒$log_{32}x+log_{32}(\frac{1}{8})=\frac{1}{5}$

⇒$log_{32}x(\frac{1}{8})=\frac{1}{5}$

⇒$\frac{x}{8}=32^{\frac{1}{5}}$

⇒$\frac{x}{8}=(2)^{5{\times}\frac{1}{5} }$

⇒$\frac{x}{8}=2$

⇒$x=8{\times}2$

⇒$x=16$