Question

If log4 256+log3 81-log2 x=0, then x=0

Answer 1

Answer:

256

Step-by-step explanation:

this is the answer for your question

Answer 2

Given expression is $log_4256+log_381-log_2 x=0$

We need to find the value of the variable x.

What is a logarithm?

The opposite of exponentiation is the logarithm. This indicates that the exponent to which a fixed number, base b, must be raised in order to create a specific number x, is represented by the logarithm of that number.

Now

$log_4256+log_381-log_2x=0\\\Rightarrow log_4(4)^4+log_3(3)^4-log_2x=0\\\Rightarrow 4log_44+4log_33-log_2x=0 \ \ \ \ \ [\because log_ex^m=mlog_ex, \ where \ m=constant]\\\Rightarrow 4+4-log_2x=0\\\Rightarrow log_2x=8\\\Rightarrow x=2^8\\\Rightarrow x=256$

therefore, the required answer is 256.

To learn more about logarithm from the given link

https://brainly.in/question/6663314

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