Question

If log4, log(2x + 2), log(2x+2 + 1) are 3 consecutive
terms of an arithmetic progression then x lies between
2 consecutive natural numbers p and q (p < q) find the
value of (p + 9)​

Answer 1

Answer:

2log(2x+2) =log4+log(2x+3) [property of ap]

log(2x+2) ^2=log 4(2x+3)

so( 2x+2) ^2=8x+12

4x^2+8x+4=8x+12

now solve for x