if log5=0.6989, log7=0.8450 then find log 3500
Answers
Answered by
2
Here, log 5 = 0.6989
log 7 = 0.8450
So, log 3500 = log 7*5*100
We know that log abc = log a+ log b+log c.
So, log 7 +log 5 + log 100
= 0.8450 + 0.6989 + 2
= 3.5439
.....Hope you understood .....
log 7 = 0.8450
So, log 3500 = log 7*5*100
We know that log abc = log a+ log b+log c.
So, log 7 +log 5 + log 100
= 0.8450 + 0.6989 + 2
= 3.5439
.....Hope you understood .....
Answered by
0
hello users ........
we have given values
log 5 = 0.6989 and log 7 = 0.8450
we have to find
log 3500 = ?
solution
we know that
log mn = log m +log n
and
log m/n = log m - log n
here
log 3500 = log 7 * 500 = log 7 + log 500
= log 7 + log 5 * 100
= log 7 +log 5 + log 100
= 0.6989 + 0.8450 + 2 ( because log 10² = 2 log 10 = 2)
= 3.5439 answer
✪✪hope it helps ✪✪
we have given values
log 5 = 0.6989 and log 7 = 0.8450
we have to find
log 3500 = ?
solution
we know that
log mn = log m +log n
and
log m/n = log m - log n
here
log 3500 = log 7 * 500 = log 7 + log 500
= log 7 + log 5 * 100
= log 7 +log 5 + log 100
= 0.6989 + 0.8450 + 2 ( because log 10² = 2 log 10 = 2)
= 3.5439 answer
✪✪hope it helps ✪✪
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