Math, asked by hazel3, 1 year ago

if log5=0.6989, log7=0.8450 then find log 3500

Answers

Answered by Monu631
2
Here, log 5 = 0.6989
log 7 = 0.8450
So, log 3500 = log 7*5*100
We know that log abc = log a+ log b+log c.
So, log 7 +log 5 + log 100
= 0.8450 + 0.6989 + 2
= 3.5439

.....Hope you understood .....
Answered by Ankit1408
0
hello users ........

we have given values 
log 5 = 0.6989 and log 7 = 0.8450 

we have to find 
log 3500 = ?

solution 
we know that 
log mn = log m +log n 
and 
log m/n = log m - log n 

here 
log 3500 = log 7 * 500 = log 7 + log 500 
= log 7 + log 5 * 100 
= log 7 +log 5 + log 100 
=  0.6989 + 0.8450 + 2           ( because log 10² = 2 log 10 = 2)
=  3.5439 answer 

✪✪hope it helps ✪✪
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