Question

if log7.log2log pie x vanishes find the value of x​

Answer 1

Answer:

If log7. Log2. Log pi (x) vanishes means it becomes zero then Log2. Log pi (x)=1

If Log2. Log pi (x) =1 then log pi (x)=2

If logpi(x) =2 then x=(pi) ^2

Hence your answer is option A that is (pi) ^2

Answer 2

Therefore the value of log₇ log₂ logₙ x where n = π is π². ( Option-a )

Given:

Logarithmic number = log₇ log₂ logₙ x where n = π

To Find:

The value of 'x'.

Solution:

The solution for the given question is shown below.

Let y = log₇ log₂ logₙ x where n = π

To vanish the value of given logarithm, y should be equated to zero.

⇒ log₇ log₂ logₙ x = 0 where n = π

⇒ log₂ logₙ x = 7⁰ = 1    [ if logₐ x = 0 then x = a⁰ ]

⇒ logₙ x = 2¹                 [ if logₐ x = 1 then x = a¹ ]

⇒ x = n²                        [ if logₐ x = 2 then x = a² ]

But n = π so x = π²

Therefore the value of log₇ log₂ logₙ x where n = π is π².

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