If log72 = m, then log4928 is equal to ?
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. : . log72 =m
Then log4928=?
log4928=log[5000-72]
= log 5000/Iog72
= log 5X1000/m
=[ log 5+ log1000]/m
=[0.6989 +3]/m
= 3.6989 /m
Then log4928=?
log4928=log[5000-72]
= log 5000/Iog72
= log 5X1000/m
=[ log 5+ log1000]/m
=[0.6989 +3]/m
= 3.6989 /m
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