If loga/b+logb/a= log (a + b), then value of (a+b)
#maths
Answers
Answered by
9
good question.
loga+ logb= log (a + b) ba
so, a+b= 1
hope it helps.
loga+ logb= log (a + b) ba
so, a+b= 1
hope it helps.
PulkitStar:
praneeth mark it brainliest please.
Answered by
32
Hi friend,
loga/b+logb/a=log(a+b)
But logx/y=logx-logy
So,
loga-logb+logb-loga=log(a+b)
0=log(a+b)
but log1=0
log1=loga+b
a+b=1
HOPE THIS HELPS
loga/b+logb/a=log(a+b)
But logx/y=logx-logy
So,
loga-logb+logb-loga=log(a+b)
0=log(a+b)
but log1=0
log1=loga+b
a+b=1
HOPE THIS HELPS
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