Question

if loga+logb=log(a+b) then prove that b=a/a-1

Answer 1

log a + log b = log(a+b)
log(a.b)=log(a+b)
(On comparing)
a×b = a+b
b=(a+b)/a
b=1+(b/a)
b-(b/a)=1
(ab-b)/a=1
b(a-1)=a
b=a/(a-1)
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