if logax=s nd logay=t , then loga(xy)2 =?
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1
add both equations
logax +logay=s+t formula {logx+logy=log(xy)}
loga(xy)=s+t
multiply by 2 on both sides
2loga(xy)=2(s+t) formula {mlogx =logx^m}
====> loga(xy)2=2(s+t)
Answered by
0
if logax=s nd logay=t , then loga(xy)2 =?
your answer is 2(s+t)
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