If logb(a)=logc(b)=loga(c) then
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Answer:
00000000000000900000000000
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the answer in given step-by-step explanation
Step-by-step explanation:
We can write logba=logalogb and similarly logca=logalogc. Expanding like this, we have,
logbalogca+logablogcb+logaclogbc=3
⇒(loga)2logblogc+(logb)2logalogc+(logc)2logalogb=3
⇒(loga)3+(logb)3+(logc)3logalogblogc=3
⇒(loga)3+(logb)3+(logc)3=3logalogblogc...(1)
Let loga=x,logb=y,logc=z. Then equation (1) transforms to
x3+y3+z3=3xyz⇔x+y+z=0
Then,
loga+logb+logc=0
⇒logabc=0
⇒abc=100=1
hope it's helpful for you
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