Question

If logg x + log4 X + log2x =11, then the value of x is?​

Answer 1

Answer:

step by step explanation :

• logx + log 4x + log 2x = 11

logx + logy = log xy

• log(x.4x.2x) = 11

• log (8x^3) = 11

• 8x^3 = e^11

• x = cuberoot{e^11/8}

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