if logm to the base a = n express a^n-1 in terms of a and m
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log m base a=n
a^n=m
now a^n-1
=a^n*a^-1
=m*1/a
=m/a
a^n=m
now a^n-1
=a^n*a^-1
=m*1/a
=m/a
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Answer:
m divided by a heeeeheeeehe
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