If logo.3(x-1) < logo.09 (x-1), then x lies in the interval
Answers
Answered by
2
log
0.3
(x−1)0.09
(x−1)
Upon applying log rules, we get,
log
0.3
(x−1)0.3
(
x−1
)
⇒x−1>
x−1
and
x−1
>0
Now,
x−1>
x−1
(
x−1
)
2
<(x−1)
2
x−12
−2x+1
x<1orx>2
Now,
x−1≥0:x≥1
Overlapping all the intervals, we get,
x>2
I hope I have helped you and if you find my answer right then please give me thanks and mark me as brainliest if you think I am correct and have helped you
0.3
(x−1)0.09
(x−1)
Upon applying log rules, we get,
log
0.3
(x−1)0.3
(
x−1
)
⇒x−1>
x−1
and
x−1
>0
Now,
x−1>
x−1
(
x−1
)
2
<(x−1)
2
x−12
−2x+1
x<1orx>2
Now,
x−1≥0:x≥1
Overlapping all the intervals, we get,
x>2
I hope I have helped you and if you find my answer right then please give me thanks and mark me as brainliest if you think I am correct and have helped you
Similar questions
Computer Science,
3 months ago
Math,
3 months ago
Hindi,
3 months ago
Social Sciences,
6 months ago
Social Sciences,
10 months ago
Science,
10 months ago