Question

if logpx=alpha logqx=bita then the value of log p/q x is
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Answer 1

*Given:-

log x (base p) = a

=> x = p^a

log x (base q) = b

=> x = q^b

=> p^a = q^b

=> q = p^(a/b)

=> p/q = p^(1 -a/b)

log x (base p/q)

= log x (base p^(1 - a/b))

= log p^a (base p^(1 - a/b)

= a/(1-a/b)

= ab/(b-a)

Hence ,

option a) is correct.

• a)
• $a) \: \frac{ \alpha \beta }{ \beta - \alpha }$