if logpx=alpha logqx=bita then the value of log p/q x is
plssss don't spam
Attachments:
Answers
Answered by
8
*Given:-
log x (base p) = a
=> x = p^a
log x (base q) = b
=> x = q^b
=> p^a = q^b
=> q = p^(a/b)
=> p/q = p^(1 -a/b)
log x (base p/q)
= log x (base p^(1 - a/b))
= log p^a (base p^(1 - a/b)
= a/(1-a/b)
= ab/(b-a)
Hence ,
option a) is correct.
- a)
Similar questions