Question

if logs 64 + logs 1/125 + 2 log2 8 = x, what is the value of x?​

Answer 1

$log64 + log( \frac{1}{125} ) + 2 log_{2}(8) = x \\ \\ log(2 {}^{6} ) + log(1) - log(5 {}^{3} ) + 2 log_{2}( {2}^{3} ) \\ \\ 6 log(2) + 0 - 3 log(5) + 2 \times 3 log_{2}(2) \\ \\ 6 \times 0.301 - 3 \times 0.698 + 3 \times 1 \\ \\ 1.806 - 2.094 + 3 \\ \\ 4.806 - 2.094 \\ \\ 2.712 \: \: \: \: ans$