Question

If Logx (1 / 8) = - 3 / 2, then x is equal to​

Answer 1

Logx (1/8) = - 3 / 2

1/8={x}^{(-3/2)}

1/8=1/x^3/2

x^3/2=8

$</p><p> \sqrt{ {x}^{3} } = 8 \\ {x}^{3} = 64 \\ x = \sqrt[3]{64} \\ x = 4$

PLS. MARK AS BRAINLIEST

Answer 2

Answer:

if Logx (1 / 8) = - 3 / 2, then x is equal to

Rewrite the logarithmic equations using exponential equation

x^logx(1/8)=x^-3/2

1/8=x^-3/2

8=x^3/2

cube root on both sides

2=x^1/2

x=2^2=4