Question

if Logx (1 / 8) = - 3 / 2, then x is equal to
A. - 4 
B. 4 
C. 1 / 4 
D. 10​

Answer 1

Answer

Option B) 4

Explanation

Given,

$\sf log_x(\frac{1}{8}) = \frac{-3}{2}$

We know that,

$\sf log_a(N) = y$

can be written as

$\sf a^y = N$

Hence, we can write it as

$\sf x^{(\frac{-3}{2})} = \frac{1}{8}$

Raising to the power of -1 on both sides, it becomes

$\sf x^{(\frac{3}{2})} = 8$

Hence,

$\sf x = 8^{(\frac{2}{3})}$

→ x = 4

Answer 2

option b is the correct one ...

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