Question

If logx/2=logy/3=logz/5 then yz=

Answer 1

Answer:

remember that a*log(b) = log%28%28b%5Ea%29%29

log(x)

log(x) = 2/3 * log(y) = log(y^(2/3)).

Remember if log(a) = log(b) then a=b

x = y^(2/3)

Similarly x = z^(2/5)

y^(2/3) * y^(1/3) = y. y^(1/3) = sqrt(x) so y = x*sqrt(x)

z^(2/5) * z^(2/5) * z^(1/5) = z. z^(2/5) = x, so that's x*x*sqrt(x) = x^2 * sqrt(x).

yz = x%2Asqrt%28x%29+%2A+x%5E2+%2A+sqrt%28x%29+=+x%5E4

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