Question

If logx 4=
-1÷3,then x=​

Answer 1

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★ Given -

$\longrightarrow \: \rm \: log_ {x} \: 4 = \frac{ - 1}{3}$

★ To Find -

$\mapsto \rm \: the \: value \: of \: x$

★ Solution -

$\rm \: since \\ \\ \mapsto\rm log_{x} \: 4 = \frac{ - 1}{3} \\ \\ \rm \: so \\ \\ \mapsto \rm \: 4 = {x}^{ \frac{ - 1}{3} }$

$\rm \: cubing \: both \: sides \\ \\ \rm \mapsto \: {4}^{3} = {x}^{ \frac{ - 1}{3} \times 3 } \\ \\ \rm \mapsto \: 64 = {x}^{ - 1} \\ \\ \rm \mapsto \frac{1}{x} = 64 \\ \\ \rm \mapsto \: x = \frac{1}{64} \: or \: {4}^{ - 3}$

★ Formula used -

${\rm{log_{a}b=c}}$

${\rm{\implies a^{c} =b}}$

Answer 2

Step-by-step explanation:

Plz refer to the attachment........

Hope it helps u.....

AAKASHIAN HERE......