Question

If logx/a = logy/3 = logz/5 = k and x^4.y^2.z^-2 = 1. Then value of a.​

Answer 1

Answer:

Given logx/a=k=>logx=AK=>x=b^ak

taking the base of logarithmas b.

similarly y=b^2k and z=b^5k

Also given x^4y^3z^-2=1

=>b^4akb^6kb^-10k=1

=>b^(4ak-4k)=1

=>4ak-4k=0

=>a=1