Question

if logx-log(2x-3)= 1 then x=​

Answer 1

logx-log(2x-3)=1

log(x/2x-3)=1

Apply exponential both sides

x/2x-3=e

x=(2x-3)e

x=2xe-3e

x-2xe+3e=0

x(1-2e)=-3e

x=-3e/(1-2e)

x=3e/(2e-1)