Question

If logx to base 4+logx to base 2=6 then x=?

Answer 1

$log_{4}(x) + log_{2}(x) \\ log_{2}(x ^{1 \div 2} ) + log_{2}(x) \\ log_{2}(x ^{1 \div 2} \times x) \\ log_{2 }(x^{3 \div 2} ) = 6 \\ 2 ^{6} = {x}^{3 \div 2 } \\ {2}^{6 \times 2 \div 3} = x \\ x = {2}^{4}$