Question

if <A =60°, then 3sin^3 A-sinA= ​

Answer 1

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Given-

A=60°

sin60°=

$\frac{ \sqrt{3} }{2}$

now solving:

$3 \times \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} = 3 \times \frac{3 \sqrt{3} }{8} \\ = \frac{9 \sqrt{3} }{8}$

then,

$\frac{9 \sqrt{3} }{8} - \frac{ \sqrt{3} }{2} = \frac{9 \sqrt{3 } }{8} - \frac{4 \sqrt{3} }{8} \\ \frac{5 \sqrt{3} }{8}$

Hope it helps

Answer 2

Hope it will be helpful