If lx+my+3=0 and 3x-2y-1=0 represent the same line, find the values of l and m.
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Answered by
4
look at the line 3x-2y=1
put x=1 ,,u get y=1
put x=3,y=4
so solution of line are (1,1),(3,4)..so these will satisfy lx+my+3=0
put these points
u get
l+m=-3
3l+4m=-3
solve these two eqns u will get l and m
put x=1 ,,u get y=1
put x=3,y=4
so solution of line are (1,1),(3,4)..so these will satisfy lx+my+3=0
put these points
u get
l+m=-3
3l+4m=-3
solve these two eqns u will get l and m
Answered by
0
Answer:
Answer is l/(1/3) = m/(-1/2) = -n/(7). Hence 3l=-2m=-n/7
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