Question

If m=(-1)^2000 and n= (-1)^2002, then find the value
of m & n
(a) – 1
(c) 2000
(b) 1
(d) 2002​

Answer 1

Answer:

both are having even values as power.so both will become 1 . (option b)

(-1)^2000= 1.

(-1)^2002= 1.

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Answer 2

The value of m/n is 1.

Given,

m = $(-1)^{2000}$

n = $(-1)^{2002}$

To Find,

The value of m/n.

Solution,

Let's solve the question using the given details.

m = $(-1)^{2000}$

n = $(-1)^{2002}$

m/n = $(-1)^{2000}$/ $(-1)^{2002}$

We will use the form,

$a^{m} /a^{n} = a^{m-n}$

So,

m/n = $-1^{2000-2002}$

On solving, we get,

m/n = .$-1^{-2}$

We will use another form,

$a^{-m} = \frac{1}{a^{m} }$

= 1/ $-1^{2}$

= 1/1

m/n = 1.

The value of m/n is 1.

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