If m = 1 3−2√2 and n = 1 3+2√2 , Find i. m 2 ii. n 2 iii. mn
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Answer:
- m² = 177 - 52√2
- n² = 177 - 52√2
- mn= 161
Step-by-step explanation:
m² = (13 - 2√2)² = 169 + 8 - 52√2 = 177 - 52√2
- (a-b) ² = a² + b² - 2ab
n² = (13 + 2√2)² = 169 + 8 + 52√2 = 177 - 52√2
- (a+b)² = a² + b² + 2ab
MN = (13 - 2√2)(13 + 2√2) = 169 - 8 = 161
- (a+b)(a-b) = a² - b²
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