Question

if m- 1/m-2 =6 find the value of (m-2)^2+ 1/(m-2)^2​

Answer 1

Answer:

$if \: \frac{1}{m} - 2 = 6 \\ then \: < m - 2 >^{2} + \frac{1}{m - 2} ^{2} \\ < m - 2 >^{2} + 36 \\ {m}^{2} + 4 + 4m + 36 \\ {m}^{2} + m + 40 = 0$

bas bro yaha tak hi solve kr paya