If m-1/m-2 = 6 then (m-2)^2 + 1/(m-2)^2 = ?
Answers
Answered by
13
this is accurate answer
Attachments:


Answered by
5
Given (m - 1)/(m - 2) = 6.
Now,
(m - 1) = 6(m - 2)
= > m - 1 = 6m - 12
= > m = 6m - 11
= > m = 11/5.
Now,
m - 2 = (11/5) - 2
= 1/5.
1/(m - 2) = 5.
Now,
(m - 2)^2 = (1/5)^2
= 1/25.
1/(m - 2)^2 = 25.
Therefore,
= > (m - 2)^2 + 1/(m - 2)^2
= > (1/25) + 25
= > 626/25.
Hope it helps!
Now,
(m - 1) = 6(m - 2)
= > m - 1 = 6m - 12
= > m = 6m - 11
= > m = 11/5.
Now,
m - 2 = (11/5) - 2
= 1/5.
1/(m - 2) = 5.
Now,
(m - 2)^2 = (1/5)^2
= 1/25.
1/(m - 2)^2 = 25.
Therefore,
= > (m - 2)^2 + 1/(m - 2)^2
= > (1/25) + 25
= > 626/25.
Hope it helps!
siddhartharao77:
:-)
Similar questions
Math,
9 months ago
Geography,
9 months ago
Accountancy,
1 year ago
Hindi,
1 year ago
Math,
1 year ago