If M-1\m-2=6; THEN WHAT IS THE VALUE
OF (M.2) 4 chase
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Answer:
Step-by-step explanation:
Given (n+3)!=56[(n+1)!]
⟹
(n+1)!
(n+3)!
=56
⟹
(n+1)!
(n+3)(n+2)(n+1)!
=56
⟹(n+3)(n+2)=8×7
⟹n+2=7
⟹n=7−2
⟹n=5
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