Math, asked by rahulkoushik1952, 2 months ago

If M-1\m-2=6; THEN WHAT IS THE VALUE
OF (M.2) 4 chase

Answers

Answered by adityaraj32893

0

Answer:

Step-by-step explanation:

Given (n+3)!=56[(n+1)!]

⟹

(n+1)!

(n+3)!

=56

⟹

(n+1)!

(n+3)(n+2)(n+1)!

=56

⟹(n+3)(n+2)=8×7

⟹n+2=7

⟹n=7−2

⟹n=5

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