Question

if m-1/m= 3,then fimd the value of m2+1/m2 plz fast​

Answer 1

$m - \frac{1}{m} = 3$

$by \: squaring \: both \: the \: sides \: we \: get - - - - -$

$(m - \frac{1}{m} )^{2} = {3}^{2}$

${m}^{2} + { \frac{1}{m} }^{2} - 2 \times m \times \frac{1}{m} = 9$

${m}^{2} + { \frac{1}{m} }^{2} - 2 = 9$

${m}^{2} + { \frac{1}{m} }^{2} = 9 + 2$

${m}^{2} + { \frac{1}{m} }^{2} = 11$

Answer 2

Step-by-step explanation:

ringboththesidesweget−−−−−

(m - \frac{1}{m} )^{2} = {3}^{2}(m−

m

1

)

2

=3

2

{m}^{2} + { \frac{1}{m} }^{2} - 2 \times m \times \frac{1}{m} = 9m

2

+

m

1

2

−2×m×

m

1

=9

{m}^{2} + { \frac{1}{m} }^{2} - 2 = 9m

2

+

m

1

2

−2=9

{m}^{2} + { \frac{1}{m} }^{2} = 9 + 2m

2

+

m

1

2

=9+2

{m}^{2} + { \frac{1}{m} }^{2} = 11m

2

+

m

1

2

=11