Math, asked by dnuska, 10 months ago

if m-1/m=41,find
I. m*2+1/m*2
2.m*4+1/m*4
3.m*2-1/m*2..​

Answers

Answered by priyankad189owcwwe
0

Answer:

1. m*2+1/m*2≈82

2. m*4+1/m*4≈164

3. m*2-1/m*2=81.98

Step-by-step explanation:

m-\frac{1}{m} =41

\frac{m^{2}-1 }{m} =41

\ m^{2}-1 } =41m

\ m^{2}-41m-1=0

m=\frac{41+\sqrt[2](41^{2} -4*1*1 )}{2*1}  or  m=\frac{41-\sqrt[2](41^{2} -4*1*1) }{2*1}

m=\frac{41+\ 41}{2}  or  m=\frac{41-41 }{2}

m=41 or m=0

⇒1. m*2+1/m*2≈82

2. m*4+1/m*4≈164

3. m*2-1/m*2=81.98

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