Question

if (m)-1/m=5 , find (m^2)-(1/m^2)​

Answer 1

Answer:

(i) m2 + (1/m2) = (m – (1/m))2 + 2

= (5)2 + 2 = 25 + 2 = 27

(ii) m4 + (1/m4) = (m2 + (1/m2)2 – 2

= (27)2 – 2 = 729 – 2 = 727

(iii) m2 – (1/m2) = (m + (1/m)) (m – (1/m))

= 5(m + (1/m))

Now, (m + (1/m))2 = (m – (1/m))2 + 4

= (5)2 + 4 = 25 + 4 = 29

∴ m + (1/m) =

∴ m2 – (1/m2) = (5) ( ) 5

Answer 2

Answer:

0

Step-by-step explanation:

m-1/m = 5

m-1=5m

-1=5m-m

-1=4m

-1/4=m

m^2=(-1/4)^2

=1/16

1/m^2=1÷1/16

=16

(m^2)-(1/m^2)=16-16

=0 (Answer)