Math, asked by SmuAd, 10 months ago

If m+1÷m=5, find the value of m^2+1÷m2​

Answers

Answered by thor100
0

Answer:

answer is 17/8

Step-by-step explanation:

m+1÷m=5

m+1=5m

m-5m= -1

-4m = -1

m= -1/-4

= 1/4

therefore,m^2+1÷2m

( 1/4)^2 +1 ÷2 (1/4)

1/16 +1 ÷ 2(1/4). ( LCM of 1/16+1)

1/16+16/16 ÷1/2

17/16 ÷1/2 = 17/8

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