if m+1/m=a and m2+pm=b then what is the value of 1+b/p+a ?
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Answered by
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m+1/m=a
=(m2+1)/m=a
m2+1=a+m
m2=a+m-1
m2 can cut m so,
m=a-1
so,
m2+pm=b
(a-2)^2+p(a-1)=b
a2+2-2a+pa-p=b
a2-2a+pa-p=b-2
a2+pa-p=b-2+2a
a(a+p)-p=b-2(1+a)
Answered by
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Step-by-step explanation:
m+1/m=a andm²+pm=b
m²+1=a+m
m²=a+m-1
m² can cut m so,
m=a-1
so
m²+pm=b
(a-2)²+p(a-1)=b
a²-2a+pa-p=b
a²+2-2a+pa-p=b
a²-2a+pa-p=b-2
a²+pa-p=b-2+2a
a(a+p)-p=b-2(1+a)
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