Math, asked by jhumakarmakar63, 28 days ago

if m+1/m=a and m2+pm=b then what is the value of 1+b/p+a ?​

Answers

Answered by hy8361438
0

m+1/m=a

=(m2+1)/m=a

m2+1=a+m

m2=a+m-1

m2 can cut m so,

m=a-1

so,

m2+pm=b

(a-2)^2+p(a-1)=b

a2+2-2a+pa-p=b

a2-2a+pa-p=b-2

a2+pa-p=b-2+2a

a(a+p)-p=b-2(1+a)

Answered by pratikborate272
0

Step-by-step explanation:

m+1/m=a andm²+pm=b

m²+1=a+m

m²=a+m-1

m² can cut m so,

m=a-1

so

m²+pm=b

(a-2)²+p(a-1)=b

a²-2a+pa-p=b

a²+2-2a+pa-p=b

a²-2a+pa-p=b-2

a²+pa-p=b-2+2a

a(a+p)-p=b-2(1+a)

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