if m = 11 + 6√2, then find the value of (√m + √2)^2
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m=11+6√2
Or, m=9+6√2+2
Or, m=(3)^2+2×3×√2+(√2)^2
Or, m=(3+√2)^2
Or, √m=+-(3+√2)
Now (√m+√2)^2
=(3+√2+√2)^2{when √m=+(3+√2)}
=(3+2√2)^2
=9+12√2+8
=17+12√2
Again when √m= -(3+√2)
(√m+√2)^2
=(-3-√2+√2)^2
=(-3)^2
=9
Or, m=9+6√2+2
Or, m=(3)^2+2×3×√2+(√2)^2
Or, m=(3+√2)^2
Or, √m=+-(3+√2)
Now (√m+√2)^2
=(3+√2+√2)^2{when √m=+(3+√2)}
=(3+2√2)^2
=9+12√2+8
=17+12√2
Again when √m= -(3+√2)
(√m+√2)^2
=(-3-√2+√2)^2
=(-3)^2
=9
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