Question

If m=15^1/3 and not =14^1/3 then find the value of m-n-1/m^2 +mn+n^2

Answer 1

Answer:

(m -n)   -  1/(m² + mn + n²) = 0

Step-by-step explanation:

If m=15^1/3 and not =14^1/3 then find the value of

(m -n)   -  1/(m² + mn + n²)

as wek know That a³ - b³ = (a - b)(a² + ab + b²)

=> 1/(a² + ab + b²)  =  (a - b)/a³ - b³

=>  1/(m² + mn + n²) = (m- n)/(m³ - n³)

= (m -n)  - (m- n)/(m³ - n³)

m³ = 15

n³ = 14

= (m - n)  - (m-n)/(15 - 14)

= (m-n) - (m-n)/1

= m-n -(m-n)

= 0

(m -n)   -  1/(m² + mn + n²) = 0

Answer 2

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