If M= 19^3 + 21^3 +23^3+25^3, then what will be the remainder if M is divided by 44?
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3
If M= 19^3 + 21^3 +23^3+25^3, then what will be the remainder if M is divided by 44?
Good question,
Here is your perfect answer!
M = 19^3 + 21^3 +23^3+25^3
= (19³ + 25³) + (23³ + 21³)
= (19+25) (19²+25²-19.25) + (23+21) (23² + 21² - 23.21)
= 44(19²+25²-19.25) + 44(23² + 21² - 23.21)
To find remainder when divided by 44,
= 44(19²+25²-19.25) + 44(23² + 21² - 23.21) /44
= 44(19²+25²-19.25)/44 + 44(23² + 21² - 23.21) /44
Hence remainder = 0, as you can see :)
Answered by
1
M = 19^3 + 21^3 + 23*23*23 + 25^3
M = 19^3 + (19+2)^3 + (19+4)^3 + (19+6)^3
M = 43912
hence, M/44 = 43912/44 = 998
Hence. Remainder is 0
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