Question

If m/2 = 1 then m = solve this question ​

Answer 1

Step-by-step explanation:

l

2

+m

2

=1

⇒m

2

=1−l

2

⇒m=±

1−l

2

Let N=l+m⇒N=l±

1−l

2

⇒

dl

dN

=1±

2

1−l

2

1

×−2l

=1±

1−l

2

l

For maximum value we have

dl

dN

=0

⇒1±

1−l

2

l

=0

⇒1−l

2

=l

2

⇒2l

2

=1

∴l=±

2

1

⇒

dl

2

d

2

N

=±

1−l

2

1−l

2

−l(

2

1−l

2

−2l

)

=±

(1−l

2

)

1−l

2

1−l

2

+l

2

=±

(1−l

2

)

2

3

1

from above l=±

2

1

=±

(1−(

2

1

)

2

)

2

3

1

=2

2

>0

N=l+

1−l

2

=

2

1

+

2

1

=

2

2

=

2

2

×

2

2

=

2

Hence the maximum value of l+m=

2

Answer 2

Answer:

l

2

+m

2

=1

⇒m

2

=1−l

2

⇒m=±

1−l

2

Let N=l+m⇒N=l±

1−l

2

⇒

dl

dN

=1±

2

1−l

2

1

×−2l

=1±

1−l

2

l

For maximum value we have

dl

dN

=0

⇒1±

1−l

2

l

=0

⇒1−l

2

=l

2

⇒2l

2

=1

∴l=±

2

1