If m/2 = 1 then m = solve this question
Answers
Answered by
0
Step-by-step explanation:
l
2
+m
2
=1
⇒m
2
=1−l
2
⇒m=±
1−l
2
Let N=l+m⇒N=l±
1−l
2
⇒
dl
dN
=1±
2
1−l
2
1
×−2l
=1±
1−l
2
l
For maximum value we have
dl
dN
=0
⇒1±
1−l
2
l
=0
⇒1−l
2
=l
2
⇒2l
2
=1
∴l=±
2
1
⇒
dl
2
d
2
N
=±
1−l
2
1−l
2
−l(
2
1−l
2
−2l
)
=±
(1−l
2
)
1−l
2
1−l
2
+l
2
=±
(1−l
2
)
2
3
1
from above l=±
2
1
=±
(1−(
2
1
)
2
)
2
3
1
=2
2
>0
N=l+
1−l
2
=
2
1
+
2
1
=
2
2
=
2
2
×
2
2
=
2
Hence the maximum value of l+m=
2
Answered by
1
Answer:
l
2
+m
2
=1
⇒m
2
=1−l
2
⇒m=±
1−l
2
Let N=l+m⇒N=l±
1−l
2
⇒
dl
dN
=1±
2
1−l
2
1
×−2l
=1±
1−l
2
l
For maximum value we have
dl
dN
=0
⇒1±
1−l
2
l
=0
⇒1−l
2
=l
2
⇒2l
2
=1
∴l=±
2
1
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