Question

if (m-2,2m+1) lies on the graph of the equation 2x+3y-10=0 find the value of m ​

Answer 1

Step-by-step explanation:

if the point (m-2,2m+1) lie on the line 2x+3y-10=0

then the points shld satisfy the equation

2(m-2)+3(2m+1)-10=p

2m-4+6m+3-10=0

8m-11=0

8m=11

m=11/8

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Answer 2

The value of m in the given point is $\frac{11}{8}$

Therefore $m=\frac{11}{8}$

Step-by-step explanation:

Given equation is $2x+3y-10=0$

Also given that the point (m-2,2m+1) lies on the graph of the given equation.

To find the value of m in the point :

• From the given the point (m-2,2m+1) lies on the graph of the given equation.
• Therefore the point must satisfy the given equation.
• That is substitute x=m-2 and y=2m+1 in the given equation $2x+3y-10=0$ we get

• $2(m-2)+3(2m+1)-10=0$
• $2(m)+2(-2)+3(2m)+3(1)-10=0$ ( by using the distributive property a(x+y)=ax+ay )
• $2m-4+6m+3-10=0$
• $8m-14+3=0$
• $8m-11=0$

• $8m=11$

$m=\frac{11}{8}$

Therefore the value of m in the given point is $\frac{11}{8}$